Low to inhibit on pin 10 makes more sense with the rest of the circuit (i think) ...
At startup, Q?? (BU810) turns on and pulls pin 10 up through R25 (?)
As the rail ramps up Z?? (12V) conducts, and the lower BC182 will eventually turn on (C?? slowing it down, as connected B-E) robbing the current that WAS pull pin 10 up ...
By that time, pin 10 is pulled up by Q?? as not much above 75V it will saturate!
But I could be talking rubbish
dc